suppose that a and 10 are relatively prime. Find the sum of all possible values of a that are less than 10. (a)20 (b)30 (c)40 (d)16
Answers
Answered by
0
For a and 10 to be relatively prime, their HCF should be 1 .
If a = 1 , then HCF is 1
a = 2 , HCF = 2
a = 3 , HCF = 1
a = 4 , HCF = 2
a = 5 , HCF = 5
a = 6 , HCF = 2
a = 7 , HCF = 1
a = 8 , HCF = 2
a = 9 , HCF = 1
a = 10 , HCF = 10
So values of a for which HCF = 1 are, 1 , 3 , 7 , 9
Sum of values of a =1 + 3 + 7 + 9 = 20
Therefore,
Sum of all possible values of a that are less than 10 is 20
Option - A.
If a = 1 , then HCF is 1
a = 2 , HCF = 2
a = 3 , HCF = 1
a = 4 , HCF = 2
a = 5 , HCF = 5
a = 6 , HCF = 2
a = 7 , HCF = 1
a = 8 , HCF = 2
a = 9 , HCF = 1
a = 10 , HCF = 10
So values of a for which HCF = 1 are, 1 , 3 , 7 , 9
Sum of values of a =1 + 3 + 7 + 9 = 20
Therefore,
Sum of all possible values of a that are less than 10 is 20
Option - A.
Similar questions