Question

9. Initial momentum of a body is 400 kg m/s and it changes to 1000 kg m/s in 20 s, on the application of a force. Find (a) change in momentum, (b) rate of change of momentum, and (iii) force applied.

Answer 1

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mu = 400 kgm/s

mv = 1000 kgm/s

t = 20 sec

(a) change in momentum = mv - mu = 1000-400 = 600 kgm/s

(b) rate of change of momentum = (mv - mu) /t

= 600/20

= 30 kgm/s²

F = ma = m(v - u) /t = (mv - mu) / t = 30 N

$<marquee>❣️Hope it helps❣️</marquee>$

Answer 2

Answer:

Explanation:

mu = 400 kgm/s

mv = 1000 kgm/s

t = 20 sec

(a) change in momentum = mv - mu = 1000-400 = 600 kgm/s

(b) rate of change of momentum = (mv - mu) /t

= 600/20

= 30 kgm/s²

F = ma = m(v - u) /t = (mv - mu) / t = 30 N