Math, asked by vinod577, 10 months ago

9. On tossing three coins at a time find
(1 all possible outcomes.
(ii) events of occurrence of 3 heads, 2 heads, 1 head and 0 head.
(iii) probability of getting 3 heads, 2 heads, 1 head and no head.

Answers

Answered by lakshkon
21

Answer:

i) 8

ii) 1,3,3,1

iii)1/8,3/8,3/8,1/8

Step-by-step explanation:

i) When we toss three coins simultaneously then the possible of outcomes are: (HHH) or (HHT) or (HTH) or (THH) or (HTT) or (THT) or (TTH) or (TTT) respectively; where H is denoted for head and T is denoted for tail.

Therefore, total numbers of outcome are 2^3 = 8

ii) From the above list of possible events, we find that the number of favourable outcomes of

an event of occurences of 3 heads, i.e., HHH = 1

an event of occurences of 2 heads, i.e., HHT,HTH,THH = 3

an event of occurences of 1 head, i.e., HTT, THT, TTH = 3

an event of occurences of 0 head, i.e., TTT = 1

P(Getting 3 heads) = Number of outcomes of getting 3 heads / total number of possible outcomes = 1/8

P(Getting 2 heads) = Number of outcomes of getting 2 heads / total number of possible outcomes = 3/8

P(Getting 1 head) = Number of outcomes of getting 1 head / total number of possible outcomes = 3/8

P(Getting 0 head) = Number of outcomes of getting 0 head / total number of possible outcomes = 1/8

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