The degeneracies are g* g. = 3 for Ca. Find N/N, at 2500 K.
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Given: The degeneracies are g* / g = 3.
To find: N* / N at 2500 K.
Solution:
- As we have given the ratio of G* and G as 3.
- The formula for N*/N is:
N*/N = ( g* / g ) x e^(-ΔE/kT)
where, ΔE = 4.699 x 10^-19 J/molecule
k is the constant = 1.381 x 10^-23 J / K
T is temperature given= 2500 K
- So, putting the values in the above formula, we get:
N*/N = 3 x e^ { (-4.699 x 10^-19) / (1.381 x 10^-23) (2500 )
N*/N = 3.67 x 10^-6
Answer:
So the value of N* / N at 2500 K. is 3.67 x 10^-6.
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