9 p square minus 10 P + 25
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9p² - 10p + 25
on comparing this eqⁿ with
ax² + bx + c = 0
a = 9 ; b = -10 ; c = 25
D = b² - 4ac
= (-10) ² - 4 × 9 × 25
= 100 - 900
= - 800
D < 0
Therefore, the eqⁿ has imaginary roots.
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