9 people sit around 1 rectangular table and 1 circular table.each table has 6 identical seats,other table is occupied only if the first table is fully occupied.how many arrangements are possible?
Answers
Each table has 6 identical seats and other table will be occupied only when the 1st table is fully occupied.
So the occupied seats on the 2nd table will be 3 in any case.
Now if 6 people sit around Rectangular table and 3 people sit around circular table , then
Number of arrangements = (6 - 1 )! . ( 3 -1 )!
= 5! . 2!
= 120 ( 2)
= 240
Also
Now if 6 people sit around circular table and 3 people sit around Rectangular table ,
then
Number of arrangements = (6 - 1 )! . ( 3 -1 )!
= 5! . 2!
= 120 ( 2)
= 240
So total number of arrangements = 240 + 240 = 480