Math, asked by amritasaha20077, 4 months ago

9. Population of I block of Lajpat Nagar is 8000 in
the beginning of July 2010. It increases at the
rate of 5% every six months. Find the population
of I block after 18 months.​

Answers

Answered by Abhijeetroy
5

Step-by-step explanation:

Initial Population= 1000

After 6 months, population= 1000+ (5/100)*1000

= 1000+50

=1050

After 12 months, population =1050+(5/100)*1050

=1050+52.5

=1103

After 18 months, population= 1103+ 1103*(5/100)

=1103+55

=1158

Answered by Abhijit999
0

Answer:

population becomes = 9261

Step-by-step explanation:

initial pop. = 8,000

pop. after first 6 month = 100+5% of 8,000

                                        =105/100 x 8000

                                             = 8,400

pop. after next 6 month = 100+5% of 8,400

                                        =105/100 x 8400

                                             = 8,820

pop. after next 6 month = 100+5% of 8,820

                                        =105/100 x 8820

                                             = 9261

(Tip - u can also use GP if u know it )

hope it helped!.................. :)

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