9. Rajesh borrowed 50000 from Vijay at simple interest of 12% per annum for 2 years, but lent it
to Sunder on the same day at 12% per annum compound interest for 2 years. Find his gain after
2 years.
Answers
Given : Rajesh borrowed 50000 from Vijay at simple interest of 12% per annum for 2 years,
lent it to Sunder on the same day at 12% per annum compound interest for 2 years.
To Find : his gain after 2 years.
Solution:
P = 50000
R = 12 %
T = 2 Years
SI = P * R * T /100
= 50000 * 12 * 2 /100
= 12000
CI = 50000(1 + 12/100)² - 50000
=> CI = 50000(1.12)² - 50000
=> CI = 50000{(1.12)² - 1}
=> CI = 12,720
Gain = 12720 - 12000 = rs 720
Another Simpler method :
Interest earned in 1st year = 50000 * 12 * 1 /100 = 6000
Gain is the interest earned in 2nd year on interest earned in 1st year
Gain = 6000 * 12 * 1 /100 = 720 Rs
Learn More:
1. Find the difference between CI and SI on 5000 for 1 year at 2% pa
https://brainly.in/question/13187389
if the difference between the ci and si for 2 years at 12 percentage ...
https://brainly.in/question/11868846
Find the principal if the difference between CI and S.I on it at 15% pa ...
https://brainly.in/question/13200416
Answer:
₹ 90
EXPLAINATION
Given:
Present value =₹16000
Interest rate =7
2
1
%perannum= 15/2 \%$$
Time =2 years
To find the amount we have the formula,
Amount (A)=P(1+(r/100))
n
where P is the present value, r is the rate of interest, n is time in years.
Now substituting the values in above formula we get,
∴A=16000(1+(15/2)/100)
2
⇒A=16000(1+3/40)
2
⇒A=16000(43/40)
2
⇒A=16000(1894/1600)
⇒A=₹ 18490
Now, we find the compound interest,
∴ Compound interest =A–P
=18490–16000=₹ 2490
Now we find the simple interest,
Simple interest (SI)=PTR/100
where P is principle amount, T is time taken, R is rate per annum
SI=(16000×(15/2)×2)/100
=160×15
=₹ 2400
Abhay's gain at the end of 2 years=(CI–SI)
=2490–2400
=₹ 90