9. Solve the pair of linear equations 3x+y=-1 and - 2x + 3y = 19.
Hence, find the value of m, if their point of intersection lies on the line y=mx
+ 3. Ans--2,5,-1
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Answer:
Step-by-step explanation:
3x+y=-1 ----(1)
-2x+3y=19 ----(2)
Multipying eq (1) by 2 and eq (2) by 3 as LCM of 2&3 is 6
2{3x+y=-1}
6x+2y=-2 ----(3)
3{-2x+3y=19}
-6x+9y=57 -----(4)
Adding (3) & (4) eq we get
6x+2y=-2
-6x+9y=57
11y=55
y = 5
Putting the value of your in eq (1) we get
3x+5=-1
3x=-6
x=-2
Now, y=mx
5=m*-2
m=-5/2
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