9 term of ap is 32 the sum of 11 and 13 term is 94 find the first term
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5
Step-by-step explanation:
9th term = a+(9-1)d = a+8d = 32--(2)
11th term = a+(11-1)d = a+10d
13th term = a+(13-1)d = a+12d
a+10d+a+12d=94
2a+22d=94
a+11d=47---(1)
(2)-(1):
3d=15
d=5
the common difference is equal to 5
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