Question

9. Th length of a rectangle is 3/2 times of its breadth and the perimeter is 180m. Find the length and breadth.
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Answer 1

Given : The length of a rectangle is 3/2 times of its breadth and the perimeter is 180 m.

To Find : The length and breadth?

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❍ Let us assume, that the breadth of the rectangle is 'x'. Then, length of the rectangle will be $\sf{ \dfrac{3x}{2} }$.

As we know,

$\bf{ \red\bigstar \: \fbox{Perimeter_{(Rectangle)} = 2(l + b)} \: \red\bigstar }$

Where,

• l = Length
• b = Breadth

$\sf{∴ \: 2 \bigg( \dfrac{3x}{2} + x \bigg) = 180 }$

➟ $\sf{3x + 2x= 180}$

➟ $\sf{5x = 180}$

➟ $\sf{x = \dfrac{ \cancel{180}^{ \: 36} }{ \cancel{5}_{ \: 1} } }$

➟ $\color{green}{\bf{x = 36}}$

Therefore,

➲ Breadth = x = 36 m

➲ Length = 3x/2 = 54 m

Answer 2

Answer:

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Step-by-step explanation:

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