Question

9. The area of a regular hexagon of side ‘a’ units is
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Answer 1

Answer:

we can write ∠AOC=∠BOC=60∘2=30∘. Hence, we can say that ∠AOB=∠OAB=60∘. Therefore, AOB is an equilateral triangle. Hence, we can say that, the area of the regular hexagon of side 'a' is 3√32a2.

Answer 2

Answer:

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Step-by-step explanation:

Formula of Area of a Hexagon = Side x side

So Area of a hexagon which sides have a = a x a