Question

9. The base of a triangular field is three times its altitude. If the cost of levelling the field at 30.50 per sq.
metre is 7350, find its base and height​

Answer 1

We know the area of a triangle = \frac{1}{2} x (base) x (altitude)

Let the altitude of the triangle = a

therefore, base length = 3a

=> area, A = \frac{1}{2} x 3a x a

=> A = \frac{3}{2} a^{2} sq.metre

Price of levelling the field of area A = A x 30.50

Given : 30.50 A = 7350

=> A = 240.98 sq.metre

Therefore, \frac{3}{2} a^{2} = 240.98

=> a = 12.67 metre

Hence, altitude length = 12.67 metre , and base length = 38.01 metre

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