Question

9. The brown ring complex compound is formulated as
[Fe(H2O)s(NO)SO4. The oxidation state of iron is
a. 1
b. 2
c. 3
d. Zero​

Answer 1

The oxidation number of iron in the above compound can be calculate as follow:

[Fe(NO)(H2O)5]SO4 dissociate in water to liberate [Fe(NO)(H2O)5]2+ ions and SO42- ions.

The charge on NO is +1 i.e. NO+, whereas H2O ligand is neutral.

Hence the oxidation state of iron in above complex is

X + (+1) +5(0) = +2

⇒ X = +1

Therefore, iron is present in +1 oxidation state in the above complex.

hope it helps

Answer 2

ANSWER

Concept of the COORDINATION COMPOUNDS

so here , we get as ,

AQUA = 0 charge ( Neutral ligand)

Nitrosonium ion = -1 ( Mono dendate ligand )

so we get as ,

X + 5 (0) -1 = 0

X = +1

so the charge on the fe is +1