Question

9. The diagonal of a square is 8cm. Its area is:
a) 16cm2
b) 64cm2 c) 32cm2
d) 48cm2​

Answer 1

$\huge\mathbb{SOLUTION:-}$

$\sf\underline{\pink{\:\:\:\:\:\:\:Given:-\:\:\:\:\:\:\:}}$

$\sf\bullet Diagonal\:of \:square=8cm$

$\bf\underline{\red{\:\:\:\:\:\:\:A.T.Q:-\:\:\:\:\:\:\:}}$

$\sf\underline{Area\:of\:square=side{}^{2}}$

$\sf\:\:\:\:\:\:\:\:or\:\:$

$\boxed{\sf{Area\:of\:square=\dfrac{1}{2}\times (diagonal){}^{2}}}$

$\sf:\implies Area\:of\:square= \dfrac{1}{2}\times (8cm){}^{2}\\ \\ \sf:\implies Area\:of\:square=\dfrac{1}{\cancel2}\times \cancel{64}\\ \\ \sf:\implies Area=32cm{}^{2}$

● (C.) is the correct option

$\boxed{\sf{Area\:of\:square=32cm{}^{2}}}$

Answer 2

Answer:

32 cm²

Step-by-step explanation:

Let the length of square be a cm

Since as we know angle between two adjacent side of square is right angle.

Also know all side of square are equal.

Apply pythagoras here

a² + a² = 8²

2 a² = 64

a² = 32 cm²

Here a² represent product of side as it is equal to area of square.

Therefore , Area of square is 32 cm²