9. The inner diameter of a cylindrical wooden pipe is 24 cm and its outer
diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the
pipe, if 1 cm of wood has a mass of 0.6 g.
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Answered by
2
Inner radius =
2
24
=12cm
Outer radius =
2
28
=14cm
Height = Length of pipe =35cm
Volume of pipe =π(r
2
2
−r
1
2
)h
=
7
22
×(14
2
−12
2
)×35cm
3
=110×52cm
3
=5720cm
3
Mass of 1cm
3
wood =0.6kg
Mass of 5720cm
3
wood =(5720×0.6)g
=3432g
=3.432kg ✔️✔️✔️
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