Question

Expand (x+24 + 4z)^2 using suitable identity​

Answer 1

$\huge \bf {Question}$

Expand ${(x + 24 + 4z)}^{2}$ using suitable identity.

$\huge \bf {Answer}$

Identity used:-

$\green {\boxed {{(a+b+c)}^{2} = {a}^{2}+{b}^{2}+{c}^{2}+2ab+2bc+2ca}}$

Solution:-

$\rm {{(a+b+c)}^{2} = {a}^{2}+{b}^{2}+{c}^{2}+2ab+2bc+2ca}$

$\rm {{(x+24+4z)}^{2} = {x}^{2}+{24}^{2}+{4z}^{2}+2\times x\times 24+2\times 24\times 4z+2\times 4z\times x}$

$\rm {{(x+24+4z)}^{2} = {x}^{2}+576+{16z}^{2}+48x+192z+8zx}$

Know more identities!

$\rm {{(a+b)}^{2} = {a}^{2} + {b}^{2} + 2ab}$

$\rm {{(a-b)}^{2} = {a}^{2} + {b}^{2} - 2ab}$

$\rm {{(a+b)}^{3} = {a}^{3} + {b}^{3} + 3ab(a+b)}$

$\rm {{(a-b)}^{3} = {a}^{3} - {b}^{3} - 3ab(a-b)}$

Answer 2

Answer:

using (a+b+c)²= a⅔+b²+c²+2ab+2ac+2bc

(x+24 + 4z)²= x²+24²+(4z)²+2×24×x+2×24×4z+2×4z×x

x²+576+16z²+48x+192z+8xz