Math, asked by vkansh1248, 5 months ago


9. The length and the breadth of a rectangular park are in the ratio 8 : 5. A path 1.5 m wide, running all around the outside of the park has an area of 594 m². Find the dimension of the park.​

Answers

Answered by siriharshikabairy123
3

Answer:

Dimensions : 118.8m and 74.25m

Step-by-step explanation:

Let the length and breath be 8x and 5x respectively

Let the length and breath be 8x and 5x respectively According to the question,

Let the length and breath be 8x and 5x respectively According to the question, => Area of the park = 594

Let the length and breath be 8x and 5x respectively According to the question, => Area of the park = 594=> lb = 594

Let the length and breath be 8x and 5x respectively According to the question, => Area of the park = 594=> lb = 594=> (8x)(5x) = 594

Let the length and breath be 8x and 5x respectively According to the question, => Area of the park = 594=> lb = 594=> (8x)(5x) = 594=> 40x = 594

Let the length and breath be 8x and 5x respectively According to the question, => Area of the park = 594=> lb = 594=> (8x)(5x) = 594=> 40x = 594=> x = 594/40

Let the length and breath be 8x and 5x respectively According to the question, => Area of the park = 594=> lb = 594=> (8x)(5x) = 594=> 40x = 594=> x = 594/40Therefore, dimensions are

Let the length and breath be 8x and 5x respectively According to the question, => Area of the park = 594=> lb = 594=> (8x)(5x) = 594=> 40x = 594=> x = 594/40Therefore, dimensions are Length = 8x = 8(594/40)

Let the length and breath be 8x and 5x respectively According to the question, => Area of the park = 594=> lb = 594=> (8x)(5x) = 594=> 40x = 594=> x = 594/40Therefore, dimensions are Length = 8x = 8(594/40) = 118.8m

Let the length and breath be 8x and 5x respectively According to the question, => Area of the park = 594=> lb = 594=> (8x)(5x) = 594=> 40x = 594=> x = 594/40Therefore, dimensions are Length = 8x = 8(594/40) = 118.8m Breadth = 5x = 5(594/40)

Let the length and breath be 8x and 5x respectively According to the question, => Area of the park = 594=> lb = 594=> (8x)(5x) = 594=> 40x = 594=> x = 594/40Therefore, dimensions are Length = 8x = 8(594/40) = 118.8m Breadth = 5x = 5(594/40) = 74.25m

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