Question

9. The numbers 2n, n2-1 and n²+1 where n is a natural number show Pythagorean
Ans:​

Answer 1

Answer:

n, 2n2−1,2n2+1 are three numbers

n2+(2n2−1)=n2+4n4−2n2+1

=44n2+n4−2n2+1

=4n4+2n2+1

=4(n2)+2(n2+1)

=(2)2(n2+1)2=(2n2+1)2

∴ n2+(2n<

Step-by-step explanation:

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