9. The numbers 2n, n2-1 and n²+1 where n is a natural number show Pythagorean
Ans:
Answers
Answered by
0
Answer:
n, 2n2−1,2n2+1 are three numbers
n2+(2n2−1)=n2+4n4−2n2+1
=44n2+n4−2n2+1
=4n4+2n2+1
=4(n2)+2(n2+1)
=(2)2(n2+1)2=(2n2+1)2
∴ n2+(2n<
Step-by-step explanation:
make as bairn pls
Similar questions