Question

9. The numerator of a fraction is 3 more than the denominator. if the numerator and the denominator are incresed by 5 the fraction become 10/7. find the fraction.​

Answer 1

Step-by-step explanation:

Let denominator of fraction be x.

Numerator of fraction =x+3

Fraction =(x+3)/x

By the given conditions,

(x+3+5)/(x+5)=10/7

Or,( x+8)/(x+5)=10/7

Or, 10(x+5)=7(x+8)

Or, 10x+50=7x+56

Or, 10x-7x=56-50

Or, 3x=6

Or, x=2

Therefore fraction =5/2

Answer 2

Answer:

the fraction is 1/2

Step-by-step explanation:

let numerator be x and denominator be y.

ATQ

x = y + 3 or. x - y = 3. -equation 1

and

x + 5 / y + 5 = 10/7

by Cross multiply method we get

7x + 35 = 10y + 50

7x - 10y = 15. -equation 2

multiply equation 1 by 7 we get

7x - 7y = 21. -equation 3

by using elimination method in equation 2. and 3

7x - 7y = 21

7x +10y = 15

(-) - - -

3y = 6

y = 6/3

y = 2

put y = 2 in equation 1

x - y = 3

x - 2 = 3

x = 3+2

x = 5

hence fraction become 5/2