Question

9. The radius of a circle is 8 cm and the length of one of its chords is 10 cm. Find the distance of

the chord from the centre.​

Answer 1

2+3+8+90+280d jsjsiduduud

Answer 2

Step-by-step explanation:

Radius of circle (OA) = 8 cm

Chord (AB) = 12cm

Draw a perpendicular OC on AB.

We know, perpendicular from centre to chord bisects the chord

Which implies, AC = BC =

122 = 6 cm

In right ΔOCA:

Using Pythagoras theorem,

OA2 = AC2 + OC2

64 = 36 + OC2

OC2 = 64 – 36 = 28

or OC = √28 = 5.291

The distance of the chord from the centre is 5.291 cm.

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