Question

9)The roots of the quadratic equation abx²+(b²-ac)x-bc=0 are *

1 point

x=-b/a,a/b

x=b/a,-a/b

x=-c/a,c/b

x=-b/a,c/b

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Answer 1

Solution :- (By Factorization Method).

→ abx² + (b²- ac)x - bc = 0

→ abx² + b²x - acx - bc = 0

→ bx(ax + b) - c(ax + b) = 0

→ (ax + b)(bx - c) = 0

Putting Both Equal to zero Now,

→ ax + b = 0

→ ax = (-b)

→ x = (-b)/a

and ,

→ bx - c = 0

→ bx = c

→ x = (c/b) .

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Solution :- (By Discriminant Method).

Refer to image . .