9. The sum of the digits of a 2-digit number is 9. On reversing its digits, the new number obtained is 45 more than the orginal number. Find the number.
Answers
Answered by
1
Answer:
The number is 27.
Step-by-step explanation:
Let the number be 10x + y.
Given,
x + y = 9 ..... (1)
Also,
10y + x = 10x + y + 45
Substitute y = 9 - x from (1)
10(9 - x) + x = 10x + 9 - x + 45
90 - 10x + x = 9x + 54
18x = 36
x = 2
y = 9 - x
= 7
Therefore, the number is 27.
Answered by
3
Answer:
27
Step-by-step explanation:
Let x be the ones digit.
The ten's digit will be= 9-x
10(9-x)+x+45 = 10x+(9-x)
90-10x+x+45 = 10x+9-x
135-9x= 9x+9
135-9= 9x+9x
126= 18x
x= 7
9-x= 2
Therefore the no. is
10(2)+7= 20+7= 27
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