Question

9. The sum of two numbers is 64, and the second number is 16 less than the first. Find the numbers.

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Answer 1

Question :

The sum of two numbers is 64 , and second number is 16 less than the first . Find the numbers

Solution :

Method - 1 : ( Exact process )

Let first number be ' x '

Second number be ' y '

• The sum of two numbers is 64

➠  x + y = 64

➠  y = 64 - x ... (1)

• Second number is 16 less than the first

➠ y = x - 16

Sub. (1) ,

➠ 64 - x = x - 16

➠ x + x = 64 + 16

➠ 2x = 80

➠ x = 40

Sub. x value in (1) , $\;$

➠ y = 64 - 40

➠ y = 24

First number , x = 40  ★

Second number , y = 24  ★  

Method - 2 :

Let first number be ' x '

second number is 16 less than the first , so

Second number = ' x - 16 '

The sum of two numbers is 64 ,

➽ x + ( x - 16 ) = 64

➽ x + x - 16 = 64

➽ 2x = 64 + 16

➽ 2x = 80

➽ x = 40

First number , x = 40 ★

Second number , (x-16) = 24 ★

Answer 2

$\mathtt{\huge{\bf{\underline{\red{Question\: ??}}}}}$

★ The sum of two numbers is 64 , and second number is 16 less than the first . Find the numbers.

$\mathtt{\huge{\bf{\underline{\green{Answer :-}}}}}$

➙ The first number is 40 & second number is 24.

$\mathtt{\huge{\bf{\underline{\orange{Solution :-}}}}}$

Given :-

• The sum of two numbers is 64 .

• The second number is 16 less than the first.

To Find :-

• The two number being added .

Solution :-

Let first number be ' x '

So , The Second number is x - 16

According to the question , The sum of two numbers is 64 .

x + ( x - 16 ) = 64

➝ x + x = 64 + 16

➝ x + x = 80

➝ 2 x = 80

➝ x = $\cancel{\dfrac{80}{2}}$

➝ x = 40

The first number is 40 .

The Second number is x - 16 =

➝ 40 - 16 = 24

So, The Second number is 24 .

$\mathtt{\huge{\bf{\underline{\pink{Let's\:Verify :-}}}}}$

The sum of two numbers is 64

➝ x + x - 16 = 64

➝ 40 + 24 = 64

➝64 = 64

➠ Hence, Verified .

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