9) There are 5 blue beads and 7 black beads in a box. If one bead is taken without looking. a) What is the probability of getting a blue bead? b) What is the probability of a black bead?
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Step-by-step explanation:
s={5 blue beads +7 black beads}
n(s)=12
event A= blue bead ={5}
n(a)=5
p(a)=n(a)/n(s)
=5/12
event b =. black beads={7)
n(b)=7
p(b)=n(b)/n(s)
=7/12
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