Question

9. Two resistances when connected in parallel give resultant value of 2 ohm, when connected
in series the value becomes 9 ohm. Calculate the value of
each resistance.​

Answer 1

r1 +r2 = 2ohm

1/r1 + 1 / r2 = 9ohm

these are the equations go solve thrm

best of luck

Answer 2

Step-by-step explanation:

Let r

1

andr

2

be the resistance

if it connected in parallel R

eq

(parallel)=

r

1

+r

2

r

1

r

2

=2Ω...eq(1)

if it connected in series R

eq

(series)=r

1

+r

2

=9Ω..eq(2)

put the value of r

1

+r

2

andr

1

fromeq(2)ineq(1)

=

9

r

1

(9−r

1

)

=2Ω

(r

1

)

2

−9r

1

+18=0

from this we get r

1

=6Ω,3Ω

corrosponding to 6Ω we get r

2

=3Ω and 3Ωr

2

=6Ω

Hence, the value of resistance would be 3Ω and 6Ω.

Hope it helps you!!!

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