Question

9. Two years ago, a father was five times as old as his son. Two years later, his age will be
8 more than three times the age of the son. Find the present ages of father and son
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Answer 1

Answer:3

Step-by-step explanation: Son’s age=x

Father’s age two years ago=5x

Father’s age 2 years later=3x+8

Equation=5x+2=3x+8

=5x-3x=8-2

=2x=6

= x=6/2 or 3

Son’s age=3

Father’s age=8+3*3=17