Question

(9) When a resistor of 2ohm is connected to a cell of
negligible internal resistance, the current
through 2ohm resistor is 1A. If another resistor of
8ohm is connected in series with the first one, then
the current through 2ohm resistor will be about.
please guys give a correct answer​

Answer 1

Answer:

You can determine the voltage of the cell by using Ohm's law: V = I x R = 1A x 2 Ohms = 2V.

With this information and the knowledge that resistors in series add and current stays the same in a series circuit, you can use Ohm's law to determine the current through the modified circuit.

I = V/R = 2V/(2+8) Ohms = 2/10 = the answer in Amps.

Answer 2

Answer:

well done kingprince

Explanation:

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