Question

9. Write the number of atoms of each element in
the molecules of following compounds:
(a) K2CO3
(b) FeSO4
(c) Pb(NO3)2
(d) Na2s
(e) Fe2(SO4)3
(f) Pb3204​

Answer 1

Answer:

As all the compounds are present in 1 mole,

a. Atoms = (1*6)*6.022*10^23

= 36.132*10^23

b. Atoms = (1*6)*6.022*10^23

= 36.132*10^23

c. Atoms = (1*9)*6.022*10^23

= 54.198*10^23

d. Atoms = (1*3)*6.022*10^23

= 18.066*10^23

e. Atoms = (1*17)*6.022*10^23

= 102.374*10^23

f. There is nothing like Pb32O4.

I hope this helps.

Answer 2

Explanation:

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