Question

9 x square - 6 b square x minus (A^4 - b ^ 4)=0​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

x =  (b² ± a² )) / 3  or (b² + a²)/3 & (b² - a²)/3 if 9x²  - 6b²x - (a⁴ - b⁴) = 0

Step-by-step explanation:

9x²  - 6b²x - (a⁴ - b⁴) = 0

=> 9x²  - 6b²x  + (b⁴ - a⁴ )

x =  (6b² ± √(36b⁴  - 4*9(b⁴ - a⁴ )) / 2*9

=> x = (6b² ± √(36b⁴  - 36b⁴ + 36a⁴ )) / 18

=>  x = (6b² ± √(36a⁴ )) / 18

=>  x = (6b² ± 6a² )) / 18

=> x = (b² ± a² )) / 3

x = (b² + a²)/3 or (b² - a²)/3

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