Question

9/y+4/x=12/√xy,where x>0and Y>0,then 3√x-2√y=?

Answer 1

9/y + 4/x = 12/√xy

9x + 4y = 12 xy/ √xy

9x + 4y = 12 √xy

9x + 4y - 12√xy = 0

{This is the expansion of (3√x - 2√y)²}

(3√x - 2√y)² = 0

{Take square root on both sides}

3√x - 2√y = 0

Hope this helps!