Math, asked by apoorwa81, 4 months ago

9 years ago, the average age of a family of five members was 33 years. Now, three new members join whose ages are in ascending order with consecutive gaps of 8 years. If the present average age of the family is the same as it was 9 years ago, what is the age (in years) of the youngest new member?

Answers

Answered by vivekvikramsingh21
0

Answer:

According to the question

Average age of 5 members today = 33 years

Sum of ages of 5 members today = 33×5 = 165 years

If the youngest member is 9 year old

∴ Sum of the age of 4 members before the birth of youngest child = 165−9−4×9

= 120 years

∴ Average = 1204 = 30 year

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