Question

9 years hence, a girl will be 3 times as old as she was 9 years ago. How old is she now?​

Answer 1

$\huge\sf\underline{\underline{\pink{ Answer:-}}}$

The girl's present age is 18 years.

$\Large{\underline{\underline{\bf{QuEsTiOn:-}}}}$

9 years hence, a girl will be 3 times as old as she was 9 years ago. How old is she now?

$\sf\underline{\underline{\green{TO \: FIND \: }}}$

The girl's present age?

$\huge\underline\mathbb{\red S\pink {0} \purple {L} \blue {UT} \orange {1}\green {ON :}}$

• Let the girl's present age be x years

• Girl's age 9 years ago = x - 9 years

• Girl's age 9 years hence = x + 9 years

$\sf\underline{\underline{\green{</strong><strong>A</strong><strong>C</strong><strong>C</strong><strong>O</strong><strong>R</strong><strong>D</strong><strong>I</strong><strong>N</strong><strong>G</strong><strong> \: </strong><strong>TO</strong><strong> \:</strong><strong> </strong><strong>T</strong><strong>H</strong><strong>E</strong><strong> </strong><strong>\</strong><strong>:</strong><strong> </strong><strong>QUESTION</strong><strong>,</strong><strong> </strong><strong>\</strong><strong>:</strong><strong> }}}$

$= > x + 9 = 3 \: ( x - 9)$

$= > x + 9 = 3x - 27$

$= > 3x - x = 9 + 27$

$= > 3x - x = 36$

$= > 2x = 36$

$= > x = \frac{36}{2}$

$= > x = 18$

$\sf\underline{\underline{\green{HENCE, \: }}}$

The girl's present age is 18 years.

Answer 2

Step-by-step explanation:

please refer to the attachment