Question

900 student approach for two papers in maths 740 student pass in first and 660 pass in second paper if 640 student pass in both find the number of student who failed in both.
Question of set theory

Answer 1

Answer:

Step-by-step explanation:

Here total students are 900

Now, let the students who passed in first paper be A and who passed in second paper be B

Therefore, (AUB) =n(A)+n(B)-n(AintersectsB)

(AUB) =740+660-640

(AUB) =760

Therefore, 760 students passed in both papers. Therefore students who failed =900-760

=140