Question

X²+px+16=0 write the value of p for which the quadratic equation. Has equal roots. Find the roots of the equation so obtained

Answer 1

It helps you to solve your difficulty

Answer 2

Answer:

8 or -8

Step-by-step explanation:

q(x)= $x^{2} +px+16=0$

It is given that it has equal roots

∴$b^{2}-4ac=0$

a=1 ; b=p ; c=16

⇒ $p^{2}-4(1)(16)=0$

   $p^{2}-64=0$

   $p^{2}=64$

   $p=$ ±$8$

And roots you can find out by any method you like.

Hope it helps...