91. A force of 50N acts on body for 10 seconds. What will be the
change in momentum (Bahawalpur 1992)
(a) 200 NS
(b)
500 N-S
(c) 800 N-S
(d) SN-
b c d
a
M
Answers
Answered by
0
Answer:
Force = dp/dt
,where dp/dt is the rate of change of linear momentum.
Given, F = 50N
dt = 1/10 s
Therefore, change in linear momentum,
dp = F * dt
= 50*1/10
= 5 Kg m/s
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