93. A test tube consists of a hemisphere and a cylinder of the same radius. The volume of
water required to fill the whole tube is 2849/3 cm and 2618/3 cm? of water is required
to fill the tube to a level which is 2 cm below the top of the tube. Find the radius of the
tube and the length of its cylindrical part.
Answers
The height is 20 cm and radius is 3.5cm
Given that, the volume of water required to fill the entire tube is = 2849/3 cm³
Also, volume of water filled upto 2cm is = 2618/3 cm³.
Let us consider r and h to be the radius and height of the test tube.
So, volume = (2/3)Пr³ + П²h
This is equal to 2849/3 cm³.
So, (2/3)Пr³ + Пr²h = 2849/3
⇒ Пr²(2r+3h) = 8547/3 ...(1)
As water is filled upto 2 cm, h' = (h-2) cm
(2/3)Пr³ + Пr²(h-2) = 2618/3
⇒ Пr²(2r/3 + h - 2) = 2618/3
⇒ Пr²(2r+3h-6) = 7854/3 ...(2)
Dividing (1) by (2),
Пr²(2r+3h)/Пr²(2r+3h-6) = 8547/7854
⇒ (2r+3h)/(2r+3h-6) = 8547/7854
(1) - (2),
6Пr² = 8547/3 - 7854/3 = 693/3 = 231
r² = 231/6П = 12.25
r = √12.25 = 3.5 cm
Replacing the value of r in (1),
П(3.5)²(2[3.5]+3h) = 8547/3
⇒ 7+3h = 67
⇒ 3h = 67-7 = 60
h = 20cm
The radius of the tube and the length of its cylindrical part is 2.47 cm and 10.36 cm.
Step-by-step explanation:
The volume of water filled in the test tube = 2849/3 cm³
The volume of water filled up to 4 cm = 2618/3 cm³
Let radius of the test tube be r
Let height of the test tube be h
2/3 πr³ + πr²h = 2849/3 cm³
πr² (2/3 r + h) = 2849/3 cm³
πr²/3 (2r + 3h) = 2849/3 cm³
⇒ πr² (2r + 3h) = 2849 cm³ → (equation 1)
Now,
2/3 πr³ + πr²(h - 4) = 2618/3 cm³
πr² (2/3 r + h - 4) = 2618/3 cm³
πr²/3 (2r + 3h - 12) = 2618/3 cm³
⇒ πr² (2r + 3h - 12) = 2618 cm³ → (equation 2)
On dividing equation (1) by (2), we get,
(2r + 3h)/(2r + 3h - 12) = 2849/2618 → (equation 3)
On subtracting equation (2) from (1), we get,
πr²(12) = 2849 - 2618 = 231
12 × 22/7 × r² = 231
r² = 231 × 7/22 × 1/12
r² = 6.125
∴ r = 2.47 cm
Now, on substituting value of 'r' in equation 3, we get,
(2(2.47) + 3h)/(2(2.47) + 3h - 12) = 2849/2618
(4.94 + 3h)/(4.94 + 3h - 12) = 2849/2618
2618(4.94 + 3h) = 2849(4.94 + 3h - 12)
12932.92 + 7854h = 14074 + 8547h - 34188
7181 = 693h
h = 7181/693
∴ h = 10.36 cm