Question

97 baseball teams participate in an annual state tournament. the champion is chosen for this tournament by the usual elimination scheme. that is, the 97 teams are divided into pairs, and the two teams of each pair play against each other. the loser of each pair is eliminated, and the remaining teams are paired up again, etc. how many games must be played to determine a champion?

Answer 1

Hey. MATE

Since the teams coming in the next round cannot be expressed as 97 /2 = 48.5 , therefore we separate a ream to make the teams an even number.


Therefore total of 7 games are played to decide the winner.

Hope it helps #))

Answer 2

Answer:

number of games required to get winner of match with 97 baseball teams under specified conditions is

96 games.

Step-by-step explanation:

$\frac{(97-1)}{2}=48 \\ \frac{48 }{2}=24 \\ \frac{24}{2}=12 \\ \frac{12}{2}=6 \\ \frac{6}{2}=3</p><p> \\ \frac{3 + 1}{2}=2 \\ \frac{2}{2}=1$

first one team had removed in 97 added and which was added in second last step,

therefore total number of games that are required to get a winner is ,

48+24+12+6+3+2+1=96

#SPJ2.