Question

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98 points..
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☺please HELP ME FRNDS......
abd give STEP BY STEP ANS..☺☺​

Answer 1

Answer:

Step-by-step explanation:

$Given: \left[\begin{array}{ccc}xp+y&x&y\\py+z&y&z\\0&xp+y&yp+z\end{array}\right] =0$

$Applying \; R_{3} \rightarrow R_{3} - p(R_{1} + R_{2})$

$\Longrightarrow\left[\begin{array}{ccc}xp+y&x&y\\py+z&y&z\\-(xp^2+2yp+z)&0&0\end{array}\right] =0$

$\Longrightarrow-(xp^2+2yp+z)(xz-y^2) = 0$

$\Longrightarrow (xz-y^2)=0$

$\Longrightarrow y^2 = xz$

$\Longrightarrow\boxed{x,y,z \;are \;in \;G.P}$

Hope it helps!

Answer 2

ANSWER

hope it helps you dear