Question

(98) square using identities find

Answer 1

Hey friend here is your answer....
Hope it helps you...
(98)^2
[Using identity (a-b)^2=a^2-2ab+b^2]
(100-2)^2
(100)^2-2×100×2+(2)^2
10000-400+4
10004-400
9600...(answer)



Thank you! : )

Answer 2

${98}^{2} \\ = {(90 + 8)}^{2} \\ using \: {(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab \\ = {90}^{2} + {8}^{2} + 2 \times 8 \times 90 \\ = 8100 + 64 + 1440 \\ = 9604$
here is ur answer.
we can solve it using a plus b whole square.
mark as brainleist