Math, asked by gitanjalischoolckd, 11 months ago

(99)³

27y³+125z³

64m³+343n³​

Answers

Answered by UtkarshASK
5

Answer:

see the solutions given below

Step-by-step explanation:

Solution 1:

(99)³ = (100-1)³

Using Identity, (a-b)³ = a³-b³-3ab(a-b)

= 100³-1³-3×100×1(100-1)

= 1000000 - 1 - 300 × 99

= 1000000 - 1 - 29700

= 1000000 - 29701

= 970299

Solution 2:

27y³+125z³ = (3y)³+(5z)³

Using Identity, (a)³ + (b)³ = (a+b)(a²+b²-2ab)

= (3y+5z) [ (3y)² + (5z)² - 2×3y×5z]

= (3y+5z) ( 9y² + 25z² - 30yz )

Solution 3:

64m³ + 343n³ = (4m)³ + (7n)³

Using Identity, (a)³ + (b)³ = (a+b)(a²+b²-2ab)

= (4m+7n) [ (4m)² + (7n)² - 2×4m×7n]. = (4m+7n) (16m² + 49n² - 56mn)

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solution by UTKARSH SHARMA from MICRO EDUCATION

Answered by battlegaming552
1

Answer:

(99)³ = (100-1)³

Using Identity, (a-b)³ = a³-b³-3ab(a-b)

= 100³-1³-3×100×1(100-1)

= 1000000 - 1 - 300 × 99

= 1000000 - 1 - 29700

= 1000000 - 29701

= 970299

(i) 27y 3 + 125z 3 = (3y)3 + (5z)3 = (3y + 5z) (3y)2 − (3y)(5z) + (5z)2

= (3y + 5z)(9y 2 − 15yz + 25z 2)

(ii) 64m 3 − 343n 3 = (4m)3 − (7n)3 = (4m − 7n) (4m)2 + (4m)(7n) + (7n)2

= (4m − 7n)(16m 2 + 28mn + 49n 2)

Step-by-step explanation:

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