Question

99. In a chemical reaction catalyzed by enzyme following the Michaelis-Menten equation, what will be the concentration
of substrate when the velocity of reaction is 90% of the maximum velocity?
a. 18 km
b. 9 Km
C. 5 Km
d. 1 km
100. At E = 20 nM and substrate concentration = 40 UM, the reaction velocity V, of an enzyme is 9.6 UM 5-1. Assuming
kaat to be 600 s-1, the Km will be
a. 0.1 uM
b. 1 UM
C. 10 PM
d. 100 M
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Answer 1

Answer:

From the graph find the maximum velocity and half it i.e. Vmax/2. Draw a horizontal line from this point till you find the point on the graph that corresponds to it and read off the substrate concentration at that point. This will give the value of Km.