Question

lines PQ and RS intersect each other at point o,if angle PQR:angle ROQ=5:7 find all the angles​

Answer 1

Answer:

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Step-by-step explanation:

let angle POR =5X and angle ROQ =7X

Then 5X +7X =180 degree as POQ is a straight angle

so 12X = 180 degree

X = 15 degree

So angle POR =angle QOS=75Degree

and angle ROQ= Angle POS =105 Degree as opposite angles are equal.

Answer 2

Answer:

∠POR+∠ROQ=180o    (Linear pair of angles)

But ∠POR:∠ROQ=5:7   (Given)

Therefore, ∠POR=125×180=75o

Similarly, ∠ROQ=127×180=105o

Now, ∠POS=∠ROQ=105o   (Vertically opposite angles)

and ∠SOQ=∠POR=75o    (Vertically opposite angles)