Question

(99)ki cube by using inditites​

Answer 1

${99}^{3} \\ {(100 - 1)}^{3} \\ \\ using \: identity \: \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} - 3 {x}^{2} y + 3x {y}^{?} \\ \\ {100}^{3} - {1}^{3} - 3 \times {100}^{2} \times 1 + 3 \times 100 \times {1}^{2} \\ 1000000 - 1 - 30000 + 300 \\ 970299 \: answer$