Question

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Matt did an experiment to study the solubility of two substances. He poured 100 mL of water at 20 °C into each of two beakers labeled A and B. He put 50 g of Substance A in the beaker labeled A and 50 g of Substance B in the beaker labeled B. The solution in both beakers was stirred for 1 minute. The amount of substance left undissolved in the beakers was weighed. The experiment was repeated for different temperatures of water and the observations were recorded as shown. Experimental Observations Substance Mass of Undissolved Substance at Different Temperatures (gram) 20 °C 40 °C 60 °C 80 °C A 50 50 50 50 B 10 8 5 2 Part 1: Which, if any, substance is soluble in water? Part 2: Explain how the data helped you determine solubility for both substances for temperatures 20 °C to 80 °C.

Answer 1

ANSWER
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Part 1)

◆ Substance B

It is soluble in water because after change in temperature some amount is dissolved i.e. why a change is seen in amount of undissolved material.

Part 2)

The Data helped me to determine solubility of both substances by showing that how much variation was there in solubility by altering the temperature. The Substance which is soluble shows varaition and the insoluble one doesn't show.

◆ The above data also proves that Solubility increases on increasing temperature.

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Answer 2

Heya..

===== Answer ======

Part 1

Substance B , is soluble in water because with increase in temperature the some amount of substance get dissolve with water ...

Part 2

This data help to identify the solubility of both the substances as how much it changed in solubility with rise in temperature or how much substance is insoluble...

Thank you