A wire is 1.0 m long,0.2mm diameter and has a 10 ohms . Find the resistivity ?
Answers
Answered by
3
R = ρL / A
ρ = RA / L
= (10 Ω × π × (0.2/2 × 10^-3 m)^2) / (1 m)
= 3.141 × 10^-7 Ω.m
Resistivity of material is 3.141 × 10^-7 Ω.m
ρ = RA / L
= (10 Ω × π × (0.2/2 × 10^-3 m)^2) / (1 m)
= 3.141 × 10^-7 Ω.m
Resistivity of material is 3.141 × 10^-7 Ω.m
Answered by
2
Hey there!
Given,
Length(l) = 1 m
Diameter(d) = 0.2 mm
Radius(r) = 0.1 mm or 0.001 m
Resistance(R) = 10 Ω
Now,
Area =πr²
= 3.14 × 0.001 × 0.001
= 0.00000314 m²
We know,
Resistivity = RA/l
= 10 × 0.00000314/1
= 0.0000314 Ω m
= 3.14×10^-7 Ω m
Hope It Helps You!
Similar questions