Question

995=100+(n-1)×5 find n=?​

Answer 1

Answer:

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The three digit natural numbers divisible by

5 are 100, 105, 110, …,995

The above sequence is an A.P.

∴ a = 100, d = 105 – 100 = 5

Let the number of terms in the A.P. be n. Then, tn = 995

Since, tn = a + (n – 1)d

∴ 995 = 100 +(n – 1)5

∴ 995 – 100 = (n – 1)5

∴ 895 = (n – 1)5

∴ n – 1 = 895/5

∴ n – 1 = 179

∴ n = 179 + 1 = 180

∴ There are 180 three digit natural numbers which are divisible by 5.

Answer 2

Answer: n=180

Step-by-step explanation:

995=100+(n-1)(5)

Distribute (n-1)(5): 995=100+5n-5

Simplify: 995=5n+95

Subtract 95 from both sides: 995-95=(5n+95)-95

Simplify: 900=5n

Divide both sides by 5: 900/5=5n/5

Simplify: 180=n