Math, asked by shivamsingh0009900, 2 months ago

9a²25b²-36c²+16d²+2(12ad+30bc)​

Answers

Answered by as3801504
1

Answer:

identity

(a+b+c)

2

=(a

2

+b

2

+c

2

+2ab+2bc+2ac)

(3a+2b−4c)

2

=(9a

2

+4b

2

+16c

2

+12ab−16bc−24ac)

so according to that identity,try to converts that terms so to fit into the formula

so factors are

( {3a + 2b - 4c)}^{2}(3a+2b−4c)

Step-by-step explanation:

hope it helpful for you

Answered by karthikdodamani2004
0

Answer:

identity

(a+b+c)

2

=(a

2

+b

2

+c

2

+2ab+2bc+2ac)

(3a+2b−4c)

2

=(9a

2

+4b

2

+16c

2

+12ab−16bc−24ac)

so according to that identity,try to converts that terms so to fit into the formula

so factors are

( {3a + 2b - 4c)}^{2}(3a+2b−4c)

2

Step-by-step explanation:

Hope it's helpful for you

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