9a²25b²-36c²+16d²+2(12ad+30bc)
Answers
Answered by
1
Answer:
identity
(a+b+c)
2
=(a
2
+b
2
+c
2
+2ab+2bc+2ac)
(3a+2b−4c)
2
=(9a
2
+4b
2
+16c
2
+12ab−16bc−24ac)
so according to that identity,try to converts that terms so to fit into the formula
so factors are
( {3a + 2b - 4c)}^{2}(3a+2b−4c)
Step-by-step explanation:
hope it helpful for you
Answered by
0
Answer:
identity
(a+b+c)
2
=(a
2
+b
2
+c
2
+2ab+2bc+2ac)
(3a+2b−4c)
2
=(9a
2
+4b
2
+16c
2
+12ab−16bc−24ac)
so according to that identity,try to converts that terms so to fit into the formula
so factors are
( {3a + 2b - 4c)}^{2}(3a+2b−4c)
2
Step-by-step explanation:
Hope it's helpful for you
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