Question

-9ab (a²+12a+35) ÷ 3ab(a+5)

Answer 1

$\frac{ - \cancel{9ab}\:^{3}(a² + 12a + 35)}{\cancel{3ab}(a + 5)} \\ \\ \frac{-3(a² + 12a + 35)}{(a + 5)} \\ \\ \frac{-3(a² +7a + 5a+35)}{a+5} \\ \\ \frac{-3(a+7)\cancel{(a+5)}}{\cancel{(a+5)}} \\ \\ -3a - 21$