Question

9k² -22k -20= 0
factorise​

Answer 1

Answer:

hope it may help u.......

Answer 2

Step-by-step explanation:

$9 {k}^{2} - 22k - 20 = 0 \\ a = 9 \\ b = - 22 \\ c = - 20 \\ \: formula = > \\ k = \frac{ - b \frac{ + }{ - } \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ PUTTING \: the \: value \: \\ k = \frac{ - ( - 22) \frac{ + }{ - } \sqrt{ { - 22}^{2} - 4 \times 9 \times - 21 } }{2 \times 9} \\ \\ k = \frac{22 \frac{ + }{ - } \sqrt{484 \times 756} }{18} \\ \\ k = \frac{22 \frac{ + }{ - } \sqrt{365904} }{18} \\ \\ k = \frac{22 + \sqrt{365904} }{18} \\ \\ k = \frac{22 - \sqrt{365904} }{18}$